60=2x^2+3x-5

Solution for 60=2x^2+3x-5 equation:

60=2x^2+3x-5

We move all terms to the left:

60-(2x^2+3x-5)=0

We get rid of parentheses

-2x^2-3x+5+60=0

We add all the numbers together, and all the variables

-2x^2-3x+65=0

a = -2; b = -3; c = +65;
Δ = b2-4ac
Δ = -32-4·(-2)·65
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-23}{2*-2}=\frac{-20}{-4}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+23}{2*-2}=\frac{26}{-4}
=-6+1/2
$